3.8
Higher Derivatives
*The
second derivative is the derivative of
(x) [the derivative
of f]. We write it as
And the process continues with
higher derivatives….
y=x3
–4x2-6x+7
= 3x2-8x-6
= 6x-8
=6
y4= 0
Find
if x6+y6=36
use implicit differentiation
6x5+6y5y1= 0
Solving for
gives us:
= ![]()
To find
differentiate for
using quotient
rule. Remember y is a function of x.
u=
v= ![]()
=
![]()
![]()

Simplify.
![]()
Factor.
Substitute 36 in for ![]()
=
ß Final Answer
Find
D27cosx
The
first derivatives of cosx are:
Dcosx=
-sinx
D2cosx=-cosx
D3cosx=sinx
D4cosx=cosx
D5cosx=-sinx
We
see that the successive derivatives occur in a cycle of length 4 and in
particular Dncosx=cosx whenever n is a multiple of 4. Therefore,
D24cosx=cosx
And
differentiating 3 more times we have
D27cosx=sinx ß Final Answer