4.6 Graphing With
Calculus and Calculators
Example
Problems
Page 276
#2 F (x) = 8x5 + 45x4 +
80x3 +90x2 +200x
First
you need to put the equation into your calculator and then find the
best fit window. The table is used
best in order to find zeros. If you are
unable to see clearly enough try graphing the first derivative instead. ZoomFit under the zoom heading works best for
finding a perfect window.
ZERO for
F (x) = 0
(First
derivative >) F ‘ (x)
= 40x4 + 180x3 + 240x2 + 180x + 200
ZERO = -2
Critical Number = -2
+
+

To check
concavity you must use the second derivative
=
160x3 + 540x2 + 480x + 180
ZEROS =
-2.27
-
+
Concave
Down (-
,
-2 .27)
Concave
Up (-2 .27,
)
Therefore
a change in concavity would indicate a point of inflection.
Point of
Inflection = -2 .27
#5 For a problem involving asymptotes
you follow basically the same directions as you would with the first
example problem.
![]()
ZEROS = none
ASYMPTOTES = -1.59 , 2.55 , 0.228
Now
graph the derivative using the quotient rule to find the first
derivative.
Quotient
Rule = ![]()
U = x
=
1
V = x3
– x2 – 4x + 1
=
3x2 – 2x2 – 4x
![]()
ZEROS = 1 > to find zeros and observe the
graph fix the window by pressing graph on
your calculator and then zoom6
+ = above x-axis - = below x-axis
+
+ +
- -
The
graph is increasing from negative infinity to one, and decreasing from
one to positive infinity. This indicates a
max at one.
To check
concavity you must use the second derivative:
![]()
Now use
the graph to determine concavity. Anything
above the x-axis is considered concave up, and anything below the
x-axis is considered concave down.
CU (-
,
-1.59) (-0.51,0.228) (2.55,
)
CD
(-1.59,-0.51) (0.228,2.55_
The
point of inflection is at (-0.51,-0.19), which is where the graph
changes from increasing to decreasing.